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Horatio Seymour

Horatio Seymour ran for president in 1868. Electoral votes, popular vote and the states won in each election.

1868 Lost

Democratic
Electoral votes
80of 294
Popular vote
2,708,74447.30%
States carried
8
Running mate
Francis Blair, Jr.

Opponents: Ulysses S. Grant (214 EV).

Alabama: lostAlaskaArizonaArkansas: lostCalifornia: lostColoradoConnecticut: lostDelaware: wonDistrict of ColumbiaFlorida: lostGeorgia: wonHawaiiIdahoIllinois: lostIndiana: lostIowa: lostKansas: lostKentucky: wonLouisiana: wonMaine: lostMaryland: wonMassachusetts: lostMichigan: lostMinnesota: lostMississippiMissouri: lostMontanaNebraska: lostNevada: lostNew Hampshire: lostNew Jersey: wonNew MexicoNew York: wonNorth Carolina: lostNorth DakotaOhio: lostOklahomaOregon: wonPennsylvania: lostRhode Island: lostSouth Carolina: lostSouth DakotaTennessee: lostTexasUtahVermont: lostVirginiaWashingtonWest Virginia: lostWisconsin: lostWyomingVermont: lostNew Hampshire: lostMassachusetts: lostRhode Island: lostConnecticut: lostNew Jersey: wonDelaware: wonMaryland: wonDistrict of Columbia
States carried in 1868 (coloured), shaded by margin.

Head-to-head

Questions and answers

How many times did Horatio Seymour run for president?

1 time (1868), without winning.

How many electoral votes did Horatio Seymour win?

1868: 80.

What share of the popular vote did Horatio Seymour get?

1868: 47.3% (2,708,744 votes).

Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data