Rhode Island · 1824 presidential election
Rhode Island presidential election results 1824
John Quincy Adams carried Rhode Island, winning 4 electoral votes.
- Electoral votes
- 4
- Votes counted
- 2,344
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| John Quincy Adams | Democratic-Republican | 2,144 | 91.50% | 4 | |
| Andrew Jackson | Democratic-Republican | — | — | — | |
| Henry Clay | Democratic-Republican | — | — | — | |
| William H. Crawford | Democratic-Republican | — | — | — | |
| Total votes | 2,344 | ||||
Sources: 1824
Rhode Island in every election · All states in 1824 · Report an error
Questions and answers
Who won Rhode Island in 1824?
John Quincy Adams won Rhode Island.
How many electoral votes did Rhode Island have in 1824?
Rhode Island cast 4 electoral votes in 1824.
How many people voted for president in Rhode Island in 1824?
2,344 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data