New York · 1828 presidential election
New York presidential election results 1828
Andrew Jackson carried New York by 2.90 points (7,849 votes), winning 36 electoral votes.
- Electoral votes
- 36
- Votes counted
- 270,975
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Andrew Jackson | Democratic | 139,412 | 51.40% | 20 | |
| John Quincy Adams | National-Republican | 131,563 | 48.60% | 16 | |
| Total votes | 270,975 | ||||
Sources: 1828
New York in every election · All states in 1828 · Report an error
Questions and answers
Who won New York in 1828?
Andrew Jackson won New York by 2.90 percentage points (7,849 votes).
How many electoral votes did New York have in 1828?
New York cast 36 electoral votes in 1828, split between candidates by congressional district.
How many people voted for president in New York in 1828?
270,975 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data