Rhode Island · 1832 presidential election
Rhode Island presidential election results 1832
Henry Clay carried Rhode Island by 14.27 points (820 votes), winning 4 electoral votes.
- Electoral votes
- 4
- Votes counted
- 5,747
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Henry Clay | National-Republican | 2,871 | 50.00% | 4 | |
| Andrew Jackson | Democratic | 2,051 | 35.70% | — | |
| William Wirt | Anti-Masonic | 819 | 14.30% | — | |
| Total votes | 5,747 | ||||
Sources: 1832
Rhode Island in every election · All states in 1832 · Report an error
Questions and answers
Who won Rhode Island in 1832?
Henry Clay won Rhode Island by 14.27 percentage points (820 votes).
How many electoral votes did Rhode Island have in 1832?
Rhode Island cast 4 electoral votes in 1832.
How many people voted for president in Rhode Island in 1832?
5,747 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data