Arkansas · 1836 presidential election
Arkansas presidential election results 1836
Martin Van Buren carried Arkansas by 28.16 points (1,046 votes), winning 3 electoral votes.
- Electoral votes
- 3
- Votes counted
- 3,714
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Martin Van Buren | Democratic | 2,380 | 64.10% | 3 | |
| Hugh Lawson White | Whig | 1,334 | 35.90% | — | |
| William Henry Harrison | Whig | — | — | — | |
| Daniel Webster | Whig | — | — | — | |
| Total votes | 3,714 | ||||
Sources: 1836
Arkansas in every election · All states in 1836 · Report an error
Questions and answers
Who won Arkansas in 1836?
Martin Van Buren won Arkansas by 28.16 percentage points (1,046 votes).
How many electoral votes did Arkansas have in 1836?
Arkansas cast 3 electoral votes in 1836.
How many people voted for president in Arkansas in 1836?
3,714 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data