Illinois · 1836 presidential election
Illinois presidential election results 1836
Martin Van Buren carried Illinois by 9.38 points (3,149 votes), winning 5 electoral votes.
- Electoral votes
- 5
- Votes counted
- 33,589
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Martin Van Buren | Democratic | 18,369 | 54.70% | 5 | |
| William Henry Harrison | Whig | 15,220 | 45.30% | — | |
| Hugh Lawson White | Whig | — | — | — | |
| Daniel Webster | Whig | — | — | — | |
| Total votes | 33,589 | ||||
Sources: 1836
Illinois in every election · All states in 1836 · Report an error
Questions and answers
Who won Illinois in 1836?
Martin Van Buren won Illinois by 9.38 percentage points (3,149 votes).
How many electoral votes did Illinois have in 1836?
Illinois cast 5 electoral votes in 1836.
How many people voted for president in Illinois in 1836?
33,589 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data