Indiana · 1836 presidential election
Indiana presidential election results 1836
William Henry Harrison carried Indiana by 11.09 points (8,255 votes), winning 9 electoral votes.
- Electoral votes
- 9
- Votes counted
- 74,423
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| William Henry Harrison | Whig | 41,339 | 55.50% | 9 | |
| Martin Van Buren | Democratic | 33,084 | 44.50% | — | |
| Hugh Lawson White | Whig | — | — | — | |
| Daniel Webster | Whig | — | — | — | |
| Total votes | 74,423 | ||||
Sources: 1836
Indiana in every election · All states in 1836 · Report an error
Questions and answers
Who won Indiana in 1836?
William Henry Harrison won Indiana by 11.09 percentage points (8,255 votes).
How many electoral votes did Indiana have in 1836?
Indiana cast 9 electoral votes in 1836.
How many people voted for president in Indiana in 1836?
74,423 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data