Ohio · 1836 presidential election
Ohio presidential election results 1836
William Henry Harrison carried Ohio by 4.28 points (8,687 votes), winning 21 electoral votes.
- Electoral votes
- 21
- Votes counted
- 202,931
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| William Henry Harrison | Whig | 105,809 | 52.10% | 21 | |
| Martin Van Buren | Democratic | 97,122 | 47.90% | — | |
| Hugh Lawson White | Whig | — | — | — | |
| Daniel Webster | Whig | — | — | — | |
| Total votes | 202,931 | ||||
Sources: 1836
Ohio in every election · All states in 1836 · Report an error
Questions and answers
Who won Ohio in 1836?
William Henry Harrison won Ohio by 4.28 percentage points (8,687 votes).
How many electoral votes did Ohio have in 1836?
Ohio cast 21 electoral votes in 1836.
How many people voted for president in Ohio in 1836?
202,931 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data