Vermont · 1836 presidential election
Vermont presidential election results 1836
William Henry Harrison carried Vermont by 19.81 points (6,954 votes), winning 7 electoral votes.
- Electoral votes
- 7
- Votes counted
- 35,099
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| William Henry Harrison | Whig | 20,994 | 59.80% | 7 | |
| Martin Van Buren | Democratic | 14,040 | 40.00% | — | |
| Hugh Lawson White | Whig | — | — | — | |
| Daniel Webster | Whig | — | — | — | |
| Total votes | 35,099 | ||||
Sources: 1836
Vermont in every election · All states in 1836 · Report an error
Questions and answers
Who won Vermont in 1836?
William Henry Harrison won Vermont by 19.81 percentage points (6,954 votes).
How many electoral votes did Vermont have in 1836?
Vermont cast 7 electoral votes in 1836.
How many people voted for president in Vermont in 1836?
35,099 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data