Iowa · 1856 presidential election
Iowa presidential election results 1856
John C. Fremont carried Iowa by 8.13 points (7,505 votes), winning 4 electoral votes.
- Electoral votes
- 4
- Votes counted
- 92,310
- IA result
- R+8.1
- Compared with the nation
- 20.3 pts more Republican
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| John C. Fremont | Republican | 45,073 | 48.80% | 4 | |
| James Buchanan | Democratic | 37,568 | 40.70% | — | |
| Millard Fillmore | Whig-American | 9,669 | 10.50% | — | |
| Total votes | 92,310 | ||||
Sources: 1856
Iowa in every election · All states in 1856 · Report an error
Questions and answers
Who won Iowa in 1856?
John C. Fremont won Iowa by 8.13 percentage points (7,505 votes).
How many electoral votes did Iowa have in 1856?
Iowa cast 4 electoral votes in 1856.
How many people voted for president in Iowa in 1856?
92,310 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data