Missouri · 1860 presidential election
Missouri presidential election results 1860
Stephen Douglas carried Missouri by 0.26 points (429 votes), winning 9 electoral votes.
- Electoral votes
- 9
- Votes counted
- 165,518
- MO result
- D+25.2
- Compared with the nation
- 35.6 pts more Democratic
- Swing since 1856
- 29.2 pts to R
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Stephen Douglas | Democratic | 58,801 | 35.53% | 9 | |
| John Bell | Constitutional Union | 58,372 | 35.27% | — | |
| John C. Breckinridge | Southern Democratic | 31,317 | 18.92% | — | |
| Abraham Lincoln | Republican | 17,028 | 10.29% | — | |
| Total votes | 165,518 | ||||
Sources: 1860
Missouri in every election · All states in 1860 · Report an error
Questions and answers
Who won Missouri in 1860?
Stephen Douglas won Missouri by 0.26 percentage points (429 votes).
How many electoral votes did Missouri have in 1860?
Missouri cast 9 electoral votes in 1860.
How many people voted for president in Missouri in 1860?
165,518 votes were counted for president.
How did Missouri change from 1856 to 1860?
The margin moved 29.2 points toward the Republican ticket, from Democratic by 54.4 points to Democratic by 25.2 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data