Iowa · 1896 presidential election
Iowa presidential election results 1896
William McKinley carried Iowa by 12.57 points (65,549 votes), winning 13 electoral votes.
- Electoral votes
- 13
- Votes counted
- 521,550
- IA result
- R+12.6
- Compared with the nation
- 7.3 pts more Republican
- Swing since 1892
- 7.3 pts to R
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| William McKinley | Republican | 289,293 | 55.50% | 13 | |
| William Jennings Bryan | Democratic | 223,744 | 42.90% | — | |
| Total votes | 521,550 | ||||
Sources: 1896
Iowa in every election · All states in 1896 · Report an error
Questions and answers
Who won Iowa in 1896?
William McKinley won Iowa by 12.57 percentage points (65,549 votes).
How many electoral votes did Iowa have in 1896?
Iowa cast 13 electoral votes in 1896.
How many people voted for president in Iowa in 1896?
521,550 votes were counted for president.
How did Iowa change from 1892 to 1896?
The margin moved 7.3 points toward the Republican ticket, from Republican by 5.3 points to Republican by 12.6 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data