Rhode Island · 1896 presidential election
Rhode Island presidential election results 1896
William McKinley carried Rhode Island by 41.94 points (22,978 votes), winning 4 electoral votes.
- Electoral votes
- 4
- Votes counted
- 54,785
- RI result
- R+41.9
- Compared with the nation
- 36.6 pts more Republican
- Swing since 1892
- 37.0 pts to R
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| William McKinley | Republican | 37,437 | 68.30% | 4 | |
| William Jennings Bryan | Democratic | 14,459 | 26.40% | — | |
| Total votes | 54,785 | ||||
Sources: 1896
Rhode Island in every election · All states in 1896 · Report an error
Questions and answers
Who won Rhode Island in 1896?
William McKinley won Rhode Island by 41.94 percentage points (22,978 votes).
How many electoral votes did Rhode Island have in 1896?
Rhode Island cast 4 electoral votes in 1896.
How many people voted for president in Rhode Island in 1896?
54,785 votes were counted for president.
How did Rhode Island change from 1892 to 1896?
The margin moved 37.0 points toward the Republican ticket, from Republican by 5.0 points to Republican by 41.9 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data