Wyoming · 1912 presidential election
Wyoming presidential election results 1912
Woodrow Wilson carried Wyoming by 1.77 points (750 votes), winning 3 electoral votes.
- Electoral votes
- 3
- Votes counted
- 42,283
- WY result
- D+1.8
- Compared with the nation
- 16.8 pts more Republican
- Swing since 1908
- 17.5 pts to D
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Woodrow Wilson | Democratic | 15,310 | 36.20% | 3 | |
| William Howard Taft | Republican | 14,560 | 34.40% | — | |
| Theodore Roosevelt | Progressive | 9,232 | 21.80% | — | |
| Eugene V. Debs | Socialist | 2,760 | 6.50% | — | |
| Total votes | 42,283 | ||||
Sources: 1912
Wyoming in every election · All states in 1912 · Report an error
Questions and answers
Who won Wyoming in 1912?
Woodrow Wilson won Wyoming by 1.77 percentage points (750 votes).
How many electoral votes did Wyoming have in 1912?
Wyoming cast 3 electoral votes in 1912.
How many people voted for president in Wyoming in 1912?
42,283 votes were counted for president.
How did Wyoming change from 1908 to 1912?
The margin moved 17.5 points toward the Democratic ticket, from Republican by 15.8 points to Democratic by 1.8 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data