Nebraska · 1936 presidential election
Nebraska presidential election results 1936
Franklin D. Roosevelt carried Nebraska by 16.40 points (99,714 votes), winning 7 electoral votes.
- Electoral votes
- 7
- Votes counted
- 608,023
- NE result
- D+16.4
- Compared with the nation
- 7.9 pts more Republican
- Swing since 1932
- 11.3 pts to R
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Franklin D. Roosevelt | Democratic | 347,445 | 57.10% | 7 | |
| Alfred M. Landon | Republican | 247,731 | 40.70% | — | |
| Total votes | 608,023 | ||||
Nebraska gives two electoral votes to the statewide winner and one to the winner of each congressional district.
Sources: 1936
Nebraska in every election · All states in 1936 · Report an error
Questions and answers
Who won Nebraska in 1936?
Franklin D. Roosevelt won Nebraska by 16.40 percentage points (99,714 votes).
How many electoral votes did Nebraska have in 1936?
Nebraska cast 7 electoral votes in 1936.
How many people voted for president in Nebraska in 1936?
608,023 votes were counted for president.
How did Nebraska change from 1932 to 1936?
The margin moved 11.3 points toward the Republican ticket, from Democratic by 27.7 points to Democratic by 16.4 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data