Rhode Island · 1936 presidential election
Rhode Island presidential election results 1936
Franklin D. Roosevelt carried Rhode Island by 12.67 points (39,307 votes), winning 4 electoral votes.
- Electoral votes
- 4
- Votes counted
- 310,278
- RI result
- D+12.7
- Compared with the nation
- 11.6 pts more Republican
- Swing since 1932
- 0.9 pts to D
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Franklin D. Roosevelt | Democratic | 164,338 | 53.00% | 4 | |
| Alfred M. Landon | Republican | 125,031 | 40.30% | — | |
| Total votes | 310,278 | ||||
Sources: 1936
Rhode Island in every election · All states in 1936 · Report an error
Questions and answers
Who won Rhode Island in 1936?
Franklin D. Roosevelt won Rhode Island by 12.67 percentage points (39,307 votes).
How many electoral votes did Rhode Island have in 1936?
Rhode Island cast 4 electoral votes in 1936.
How many people voted for president in Rhode Island in 1936?
310,278 votes were counted for president.
How did Rhode Island change from 1932 to 1936?
The margin moved 0.9 points toward the Democratic ticket, from Democratic by 11.8 points to Democratic by 12.7 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data