Wyoming · 1940 presidential election
Wyoming presidential election results 1940
Franklin D. Roosevelt carried Wyoming by 5.93 points (6,654 votes), winning 3 electoral votes.
- Electoral votes
- 3
- Votes counted
- 112,240
- WY result
- D+5.9
- Compared with the nation
- 4.0 pts more Republican
- Swing since 1936
- 17.2 pts to R
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Franklin D. Roosevelt | Democratic | 59,287 | 52.80% | 3 | |
| Wendell L. Willkie | Republican | 52,633 | 46.90% | — | |
| Total votes | 112,240 | ||||
Sources: 1940
Wyoming in every election · All states in 1940 · Report an error
Questions and answers
Who won Wyoming in 1940?
Franklin D. Roosevelt won Wyoming by 5.93 percentage points (6,654 votes).
How many electoral votes did Wyoming have in 1940?
Wyoming cast 3 electoral votes in 1940.
How many people voted for president in Wyoming in 1940?
112,240 votes were counted for president.
How did Wyoming change from 1936 to 1940?
The margin moved 17.2 points toward the Republican ticket, from Democratic by 23.1 points to Democratic by 5.9 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data