Iowa · 1948 presidential election
Iowa presidential election results 1948
Harry S Truman carried Iowa by 2.73 points (28,362 votes), winning 10 electoral votes.
- Electoral votes
- 10
- Votes counted
- 1,038,264
- IA result
- D+2.7
- Compared with the nation
- 1.7 pts more Republican
- Swing since 1944
- 7.2 pts to D
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Harry S Truman | Democratic | 522,380 | 50.30% | 10 | |
| Thomas E. Dewey | Republican | 494,018 | 47.60% | — | |
| Strom Thurmond | States' Rights | -- | 0.00% | — | |
| Total votes | 1,038,264 | ||||
Sources: 1948
Iowa in every election · All states in 1948 · Report an error
Questions and answers
Who won Iowa in 1948?
Harry S Truman won Iowa by 2.73 percentage points (28,362 votes).
How many electoral votes did Iowa have in 1948?
Iowa cast 10 electoral votes in 1948.
How many people voted for president in Iowa in 1948?
1,038,264 votes were counted for president.
How did Iowa change from 1944 to 1948?
The margin moved 7.2 points toward the Democratic ticket, from Republican by 4.5 points to Democratic by 2.7 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data