Iowa · 1968 presidential election
Iowa presidential election results 1968
Richard M. Nixon carried Iowa by 12.19 points (142,407 votes), winning 9 electoral votes.
- Electoral votes
- 9
- Votes counted
- 1,167,931
- IA result
- R+12.2
- Compared with the nation
- 11.5 pts more Republican
- Swing since 1964
- 36.2 pts to R
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Richard M. Nixon | Republican | 619,106 | 53.00% | 9 | |
| Hubert Humphrey | Democratic | 476,699 | 40.80% | — | |
| George Wallace | American Independent | 66,422 | 5.70% | — | |
| Total votes | 1,167,931 | ||||
Sources: 1968
Iowa in every election · All states in 1968 · Report an error
Questions and answers
Who won Iowa in 1968?
Richard M. Nixon won Iowa by 12.19 percentage points (142,407 votes).
How many electoral votes did Iowa have in 1968?
Iowa cast 9 electoral votes in 1968.
How many people voted for president in Iowa in 1968?
1,167,931 votes were counted for president.
How did Iowa change from 1964 to 1968?
The margin moved 36.2 points toward the Republican ticket, from Democratic by 24.0 points to Republican by 12.2 points.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data