New Jersey · 1828 presidential election
New Jersey presidential election results 1828
John Quincy Adams carried New Jersey by 4.27 points (1,944 votes), winning 8 electoral votes.
- Electoral votes
- 8
- Votes counted
- 45,570
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| John Quincy Adams | National-Republican | 23,753 | 52.10% | 8 | |
| Andrew Jackson | Democratic | 21,809 | 47.90% | — | |
| Total votes | 45,570 | ||||
Sources: 1828
New Jersey in every election · All states in 1828 · Report an error
Questions and answers
Who won New Jersey in 1828?
John Quincy Adams won New Jersey by 4.27 percentage points (1,944 votes).
How many electoral votes did New Jersey have in 1828?
New Jersey cast 8 electoral votes in 1828.
How many people voted for president in New Jersey in 1828?
45,570 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data