New Jersey · 1832 presidential election
New Jersey presidential election results 1832
Andrew Jackson carried New Jersey by 0.75 points (360 votes), winning 8 electoral votes.
- Electoral votes
- 8
- Votes counted
- 47,760
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Andrew Jackson | Democratic | 23,826 | 49.90% | 8 | |
| Henry Clay | National-Republican | 23,466 | 49.10% | — | |
| William Wirt | Anti-Masonic | 468 | 1.00% | — | |
| Total votes | 47,760 | ||||
Sources: 1832
New Jersey in every election · All states in 1832 · Report an error
Questions and answers
Who won New Jersey in 1832?
Andrew Jackson won New Jersey by 0.75 percentage points (360 votes).
How many electoral votes did New Jersey have in 1832?
New Jersey cast 8 electoral votes in 1832.
How many people voted for president in New Jersey in 1832?
47,760 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data