Alabama · 1832 presidential election
Alabama presidential election results 1832
Andrew Jackson carried Alabama by 99.93 points (14,281 votes), winning 7 electoral votes.
- Electoral votes
- 7
- Votes counted
- 14,291
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Andrew Jackson | Democratic | 14,286 | 100.00% | 7 | |
| Henry Clay | National-Republican | 5 | 0.00% | — | |
| William Wirt | Anti-Masonic | — | — | — | |
| Total votes | 14,291 | ||||
Sources: 1832
Alabama in every election · All states in 1832 · Report an error
Questions and answers
Who won Alabama in 1832?
Andrew Jackson won Alabama by 99.93 percentage points (14,281 votes).
How many electoral votes did Alabama have in 1832?
Alabama cast 7 electoral votes in 1832.
How many people voted for president in Alabama in 1832?
14,291 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data