Alabama · 1836 presidential election
Alabama presidential election results 1836
Martin Van Buren carried Alabama by 10.67 points (3,980 votes), winning 7 electoral votes.
- Electoral votes
- 7
- Votes counted
- 37,296
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Martin Van Buren | Democratic | 20,638 | 55.30% | 7 | |
| Hugh Lawson White | Whig | 16,658 | 44.70% | — | |
| William Henry Harrison | Whig | — | — | — | |
| Daniel Webster | Whig | — | — | — | |
| Total votes | 37,296 | ||||
Sources: 1836
Alabama in every election · All states in 1836 · Report an error
Questions and answers
Who won Alabama in 1836?
Martin Van Buren won Alabama by 10.67 percentage points (3,980 votes).
How many electoral votes did Alabama have in 1836?
Alabama cast 7 electoral votes in 1836.
How many people voted for president in Alabama in 1836?
37,296 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data