Rhode Island · 1852 presidential election
Rhode Island presidential election results 1852
Franklin Pierce carried Rhode Island by 6.52 points (1,109 votes), winning 4 electoral votes.
- Electoral votes
- 4
- Votes counted
- 17,005
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| Franklin Pierce | Democratic | 8,735 | 51.40% | 4 | |
| Winfield Scott | Whig | 7,626 | 44.80% | — | |
| John P. Hale | Free Soil | 644 | 3.80% | — | |
| Total votes | 17,005 | ||||
Sources: 1852
Rhode Island in every election · All states in 1852 · Report an error
Questions and answers
Who won Rhode Island in 1852?
Franklin Pierce won Rhode Island by 6.52 percentage points (1,109 votes).
How many electoral votes did Rhode Island have in 1852?
Rhode Island cast 4 electoral votes in 1852.
How many people voted for president in Rhode Island in 1852?
17,005 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data