Rhode Island · 1856 presidential election
Rhode Island presidential election results 1856
John C. Fremont carried Rhode Island by 24.15 points (4,787 votes), winning 4 electoral votes.
- Electoral votes
- 4
- Votes counted
- 19,822
- RI result
- R+24.2
- Compared with the nation
- 36.4 pts more Republican
Statewide result
| Candidate | Party | Votes | Share | Bar | Electoral votes |
|---|---|---|---|---|---|
| John C. Fremont | Republican | 11,467 | 57.80% | 4 | |
| James Buchanan | Democratic | 6,680 | 33.70% | — | |
| Millard Fillmore | Whig-American | 1,675 | 8.50% | — | |
| Total votes | 19,822 | ||||
Sources: 1856
Rhode Island in every election · All states in 1856 · Report an error
Questions and answers
Who won Rhode Island in 1856?
John C. Fremont won Rhode Island by 24.15 percentage points (4,787 votes).
How many electoral votes did Rhode Island have in 1856?
Rhode Island cast 4 electoral votes in 1856.
How many people voted for president in Rhode Island in 1856?
19,822 votes were counted for president.
Official results As published by The American Presidency Project (UC Santa Barbara) and the state documents it links. How we use this data